130=5n^2

Solution for 130=5n^2 equation:

130=5n^2

We move all terms to the left:

130-(5n^2)=0

a = -5; b = 0; c = +130;
Δ = b2-4ac
Δ = 02-4·(-5)·130
Δ = 2600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2600}=\sqrt{100*26}=\sqrt{100}*\sqrt{26}=10\sqrt{26}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{26}}{2*-5}=\frac{0-10\sqrt{26}}{-10}
=-\frac{10\sqrt{26}}{-10}
=-\frac{\sqrt{26}}{-1}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{26}}{2*-5}=\frac{0+10\sqrt{26}}{-10}
=\frac{10\sqrt{26}}{-10}
=\frac{\sqrt{26}}{-1}
$